Question
You are given an absolute path for a Unix-style file system, which always begins with a slash
'/'. Your task is to transform this absolute path into its simplified canonical path.The rules of a Unix-style file system are as follows:
- A single period
'.'represents the current directory.- A double period
'..'represents the previous/parent directory.- Multiple consecutive slashes such as
'//'and'///'are treated as a single slash'/'.- Any sequence of periods that does not match the rules above should be treated as a valid directory or file name. For example,
'...'and'....'are valid directory or file names.The simplified canonical path should follow these rules:
- The path must start with a single slash
'/'.- Directories within the path must be separated by exactly one slash
'/'.- The path must not end with a slash
'/', unless it is the root directory.- The path must not have any single or double periods (
'.'and'..') used to denote current or parent directories.Return the simplified canonical path.
Ideas
- This is a stack question like Leetcode - Basic Calculator II where our
..relative directives immediately affect the last directory we processed (note here processed not the next directory in the list of directories we are processing) - We want to first split our string of paths on a “/”
- Iterating through the directories
- If curr is “.” or “” ignore it
- If there is stuff in the stack and curr is “..”, pop from stack
- Otherwise add to the stack
Don’t get tunnel vision
During this problem, I got tunnel vision trying to solve the problem where you can have multiple
..in a rowd/b/../../and I didn’t realize that my method wasn’t wrong, but rather I was mistaking the directories we are building up for our stack. When I solve problems, I need to try to prevent Tunnel Vision